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0=-4.9x^2+6x+0.6
We move all terms to the left:
0-(-4.9x^2+6x+0.6)=0
We add all the numbers together, and all the variables
-(-4.9x^2+6x+0.6)=0
We get rid of parentheses
4.9x^2-6x-0.6=0
a = 4.9; b = -6; c = -0.6;
Δ = b2-4ac
Δ = -62-4·4.9·(-0.6)
Δ = 47.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{47.76}}{2*4.9}=\frac{6-\sqrt{47.76}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{47.76}}{2*4.9}=\frac{6+\sqrt{47.76}}{9.8} $
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